JEE Main Physics question
The minimum velocity (in ms⁻¹) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is
Answer: (B)
Solution
v = √(μgR) = √(0.6×10×150) = √900 = 30 ms⁻¹.
The minimum velocity (in ms⁻¹) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is
v = √(μgR) = √(0.6×10×150) = √900 = 30 ms⁻¹.