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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A mass of 3 kg descending vertically downward supports a mass of 2 kg by means of a string passing over a pulley. At the end of 5 s, the string breaks. How much higher will the 2 kg mass go further?

Answer: (A)

Solution

Acceleration a = [(3−2)/(3+2)]g = 1.96 ms⁻². Velocity of the 2 kg mass (moving up) when the string breaks: v = at = 1.96×5 =

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Question ID VK-153081