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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A force of 50 N is applied in the horizontal direction at the mid-point of the rope. The angle made by the rope with the vertical, in the equilibrium position, will be (take g = 10 ms⁻², neglect the mass of the rope)

Answer: (D)

Solution

At the mid-point, resolving the three forces (tension to ceiling, tension to mass, applied

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Question ID VK-153084