JEE Main Physics question
The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/s to 15 cm/s in 0.2 s is
Answer: (A)
Solution
F = m(v−u)/t = 5 × (0.15 − 0.65)/0.2 = 5 × (−0.5)/0.2 = −12.5 N; magnitude 12.5 N.
The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/s to 15 cm/s in 0.2 s is
F = m(v−u)/t = 5 × (0.15 − 0.65)/0.2 = 5 × (−0.5)/0.2 = −12.5 N; magnitude 12.5 N.