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JEE Main Physics question

PhysicsMotion in a PlaneJEE Main

A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are = 2cos t, = 2 sin t. The angle between F and p at time t is

Answer: (A)

Solution

F = dp/dt, so = −2 sin t, = 2 cos t. p · F = (2cos t)(−2 sin t) + (2 sin t)(2 cos t) =

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Question ID VK-153176