JEE Main Physics question

Physics Laws of Motion JEE Main

The mass of a lift is 2000 kg. When the tension in the supporting cable is 28000 N, then its acceleration is

(A)30 ms⁻² downwards
(B)4 ms⁻² upwardsCorrect
(C)4 ms⁻² downwards
(D)14 ms⁻² upwards

Answer: (B)

Solution

T − mg = ma ⟹ a = (T − mg)/m = (28000 − 2000×10)/2000 = 8000/2000 = 4 ms⁻² (upward, since T > mg).

Question ID VK-153187