JEE Main Physics question
A player caught a cricket ball of mass 150 gm moving at the rate of 20 m/sec. If the catching process is completed in 0.1 sec, the force of the blow exerted by the ball on the hands of the player is
Answer: (B)
Solution
Δp = mv = 0.150 × 20 = 3 kg·ms⁻¹ (ball brought to rest). F = Δp/t = 3/0.1 = 30 N.