JEE Main Physics question
A man weighs 80 kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 m/s². What would be the reading on the scale? (g = 10 m/s²)
Answer: (C)
Solution
Reading = m(g+a) = 80 × (10+5) = 80 × 15 = 1200 N.