JEE Main Physics question
A particle moves in the x–y plane under the influence of a force such that its linear momentum is p⃗(t) = A[î cos(kt) − ĵ sin(kt)], where A and k are constants. The angle between the force and the momentum is
Answer: (D)
Solution
F = dp/dt = Ak[−î sin(kt) − ĵ cos(kt)]. p · F = A cos(kt)×(−Ak sin kt) + (−A sin
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