JEE Main Physics question
An army vehicle of mass 1000 kg is moving with a velocity of 10 m/s and is acted upon by a forward force of 1000 N due to the engine and a retarding force of 500 N due to friction. What will be its velocity after 10 s?
Answer: (C)
Solution
Net force = 1000 − 500 = 500 N, a = 500/1000 = 0.5 m/s². v = u + at = 10 + 0.5×10 = 15 m/s.