JEE Main Physics question
The ratio of the weight of a man in a stationary lift and when it is moving down with uniform acceleration 'a' is 3 : 2. The value of 'a' is (g = acceleration due to gravity of the earth)
Answer: (C)
Solution
: down = mg : m(g−a) = 3 : 2 ⟹ 2g = 3(g−a) ⟹ 3a = 3g − 2g = g ⟹ a = g/3.