Test SeriesFree PYQsExamsPricing

JEE Main Physics question

PhysicsLaws of MotionJEE Main

Two forces of 5 N each are applied at the two ends of a light, stretched spring, pulling it outward in opposite directions (5 N ← spring → 5 N). The tension in the spring is

Answer: (C)

Solution

For a massless spring in equilibrium with equal and opposite forces of 5 N applied at each end,

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-153204