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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A particle of mass 0.3 kg is subjected to a force F = −kx with k = 15 N/m. What will be its initial acceleration if it is released from a point 20 cm away from the origin?

Answer: (B)

Solution

At x = 0.20 m, |F| = kx = 15 × 0.20 = 3 N. a = F/m = 3/0.3 = 10 m/s².

Question ID VK-153207