JEE Main Physics question
The time period of a simple pendulum, measured inside a stationary lift, is found to be T. If the lift starts accelerating upwards with an acceleration g/3, the time period is
Answer: (B)
Solution
The effective gravity becomes g' = g + g/3 = 4g/3. Since T ∝ 1/√g', T' = T√(g/g') = T√(g/(4g/3)) = T√(3/4) = T√3/2.