JEE Main Physics question
A lift of mass 1000 kg is moving with an acceleration of 1 m/s² in the upward direction. The tension developed in the string connected to the lift is
Answer: (C)
Solution
Using g = 9.8 ms⁻² (as indicated by the answer values): T = m(g+a) = 1000 × (9.8 + 1) = 1000 × 10.8 = 10,800 N.