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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton, so that it attains a vertical height of 20 m. The time for which the ball remains in contact with the bat is (g = 10 m/s²)

Answer: (A)

Solution

Speed just before impact (falling from 5 m): u = √(2×10×5) = 10 m/s downward. Speed just after impact (to rise 20 m): v =

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Question ID VK-153224