JEE Main Physics question
In an elevator moving vertically up with an acceleration g, the force exerted on the floor by a passenger of mass M is
Answer: (D)
Solution
Normal force N = M(g+a) = M(g+g) = 2Mg.
In an elevator moving vertically up with an acceleration g, the force exerted on the floor by a passenger of mass M is
Normal force N = M(g+a) = M(g+g) = 2Mg.