JEE Main Physics question

Physics Laws of Motion JEE Main

A boy having a mass of 40 kilograms is standing in an elevator. The force felt by the feet of the boy will be greatest when the elevator (g = 9.8 metres/sec²)

(A)Stands still
(B)Moves downward at a constant velocity of 4 metres/sec
(C)Accelerates downward with an acceleration equal to 4 metres/sec²
(D)Accelerates upward with an acceleration equal to 4 metres/sec²Correct

Answer: (D)

Solution

The normal (felt) force is N = m(g+a) when accelerating upward, N = m(g−a) when accelerating downward, and N = mg when at rest or moving

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Question ID VK-153232