JEE Main Physics question
A ball of mass 0.5 kg moving with a velocity of 2 m/sec strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and the wall is one millisecond, the average force exerted by the wall on the ball is
Answer: (A)
Solution
Δp = 2mv = 2×0.5×2 = 2 kg·ms⁻¹. F = Δp/t = 2/0.001 = 2000 N.