JEE Main Physics question
A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in 1/10 sec, the required force in the opposite direction is
Answer: (A)
Solution
F = mΔv/t = 100×5/0.1 = 5000 N.
A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in 1/10 sec, the required force in the opposite direction is
F = mΔv/t = 100×5/0.1 = 5000 N.