JEE Main Physics question

PhysicsLaws of MotionJEE Main

A machine gun fires 4 bullets per second. The mass of each bullet is 20 g, and the velocity of the bullet when it leaves the gun is 300 ms⁻¹. The force required to hold the gun while firing is

Answer: (C)

Solution

Force = rate × (mass × velocity) per bullet = 4 × 0.02 × 300 = 24 N.

Question ID VK-153253