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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

If the force on a rocket, having exhaust velocity of 300 m/sec, is 210 N, then the rate of combustion of the fuel is

Answer: (A)

Solution

Thrust = (rate of combustion) × (exhaust velocity) ⟹ rate = F/ = 210/300 = 0.7 kg/s.

Question ID VK-153259