JEE Main Physics question
A man fires a bullet of mass 200 g at a speed of 5 m/s. The gun is of mass one kg. By what velocity the gun rebounds backward?
Answer: (C)
Solution
By conservation of momentum: 0.2 × 5 = 1 × v ⟹ v = 1/1 = 1 m/s.
A man fires a bullet of mass 200 g at a speed of 5 m/s. The gun is of mass one kg. By what velocity the gun rebounds backward?
By conservation of momentum: 0.2 × 5 = 1 × v ⟹ v = 1/1 = 1 m/s.