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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A bullet of mass 10 g moving with 300 m/s hits a block of ice of mass 5 kg and drops dead (embeds in it). The velocity of the ice is

Answer: (B)

Solution

By conservation of momentum (perfectly inelastic collision): 0.01 × 300 = (5 + 0.01) × v ⟹ v = 3/5.01 ≈ 0.599 m/s ≈ 60 cm/s.

Question ID VK-153289