JEE Main Physics question

Physics Laws of Motion JEE Main

Three forces F₁, F₂ and F₃ keep a body in equilibrium. If F₁ = 3 N along the positive x-axis and F₂ = 4 N along the positive y-axis, then the third force F₃ is

(A)5 N, making an angle θ = tan⁻¹(3/4) with the negative y-axisCorrect
(B)5 N, making an angle θ = tan⁻¹(4/3) with the negative y-axis
(C)7 N, making an angle θ = tan⁻¹(3/4) with the negative y-axis
(D)7 N, making an angle θ = tan⁻¹(4/3) with the negative y-axis

Answer: (A)

Solution

For equilibrium, F₃ = −(F₁+F₂) = −3î − 4ĵ, with magnitude √(3²+4²) = 5 N. The angle φ this vector makes with the

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Question ID VK-153296