JEE Main Physics question
A mass of 5 kg is suspended by a rope of length 2 m from a ceiling. A force of 50 N in the horizontal direction is applied at the mid-point of the rope. The angle made by the (upper segment of the) rope with the vertical, in equilibrium, is (g = 10 ms⁻²)
Answer: (D)
Solution
At the hanging mass, only the lower segment's tension and gravity act, so for the mass's equilibrium the lower segment must remain exactly vertical, with tension T₂ = mg = 50 N. At the midpoint (where the horizontal 50 N force is applied),
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