JEE Main Physics question
A 2 kg block is lying on a smooth table which is connected by a string passing over a pulley. The other end of the string is connected to a body of mass 1 kg hanging vertically. The acceleration of the block and the tension in the string will be (g = 9.8 ms⁻²)
Answer: (A)
Solution
a = mg/(M+m) = (1×9.8)/(2+1) = 9.8/3 = 3.27 m/s². T = Mma/m... equivalently T = Mmg/(M+m) = (2×1×9.8)/3 = 6.53 ≈ 6.54 N.