JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of mass m₁ rests on a horizontal table. A string tied to the block is passed over a frictionless pulley fixed at the end of the table, and to the other end of the string is hung another block of mass m₂. The acceleration of the system is

Answer: (A)

Solution

Treating the system as a whole: m₂g = (m₁+m₂)a ⟹ a = m₂g/(m₁+m₂).

Question ID VK-153315