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JEE Main Physics question

PhysicsLaws of MotionJEE Main

Forces F₁, F₂, F₃ are acting on a particle of mass m such that F₂ and F₃ are mutually perpendicular, and the particle remains stationary. If the force F₁ is now removed, the acceleration of the particle is

Answer: (A)

Solution

For equilibrium, F₁ = −(F₂+F₃), so |F₁| = √(F₂²+F₃²) (since F₂⊥F₃). Removing F₁ leaves a net

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Question ID VK-153326