JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of mass M, placed on a frictionless horizontal table, is pulled by another block of mass m hanging vertically by a massless string passing over a frictionless pulley. The tension in the string is

Answer: (D)

Solution

Common acceleration a = mg/(M+m). Tension (on the M side) = Ma = Mmg/(M+m).

Question ID VK-153343