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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is [AFMC 1998]

Answer: (C)

Solution

Impulse = F×t = 50 dyne × 3 s = 150 dyne-s. Converting: 1 dyne = 10⁻⁵ N, so 150 dyne-s = 150×10⁻⁵ N-s = 1.5×10⁻³ N-s.

Question ID VK-153403