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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of 1 kg is stopped against a wall by applying a force F perpendicular to the wall. If μ = 0.2, then minimum value of F will be

Answer: (B)

Solution

For the block to not fall, the friction must support its weight: μF ≥ mg ⟹ F ≥ mg/μ = (1×9.8)/0.2 = 49 N.

Question ID VK-153426