JEE Main Physics question
A body of mass 5 kg rests on a rough horizontal surface of coefficient of friction 0.2. The body is pulled through a distance of 10 m by a horizontal force of 25 N. The kinetic energy acquired by it is (g = 10 ms²)
Answer: (B)
Solution
Friction force = μmg = 0.2×5×10 = 10 N. Net force = 25−10 = 15 N. By the
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