JEE Main Physics question
A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction μ = 0.5. If a horizontal force of 100 N is acting on it, then acceleration of the block will be
Answer: (B)
Solution
Friction = μmg = 0.5×10×10 = 50 N. Net force = 100−50 = 50 N. Acceleration = 50/10 = 5 m/s².