JEE Main Physics question
A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. Then the coefficient of friction is
Answer: (D)
Solution
Deceleration a = Δv/t = 6/10 = 0.6 m/s². μ = a/g = 0.6/10 = 0.06.