JEE Main Physics question
A body of 10 kg is acted by a force of 129.4 N if g = 9.8 m/s². The acceleration of the block is 10 m/s². What is the coefficient of kinetic friction
Answer: (C)
Solution
Newton's second law: F − μmg = ma ⟹ 129.4 − μ(10)(9.8) = 10×10 = 100 ⟹ μ(98) = 29.4 ⟹ μ = 0.3.