JEE Main Physics question
A force of 750 N is applied to a block of mass 102 kg to prevent it from sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block is
Answer: (D)
Solution
Weight component along the incline (down-slope) = mg sinθ ≈ 102×9.8×0.5 ≈ 500 N. Since the applied force (750 N, acting up the incline) exceeds this driving
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