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JEE Main Physics question

PhysicsLaws of MotionJEE Main

Starting from rest, a body slides down a 45° inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of friction between the body and the inclined plane is

Answer: (C)

Solution

Smooth case: s = ½g sinθ·t₀². Rough case (t = 2t₀): s = ½g(sinθ−μcosθ)(2t₀)². Equating:

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Question ID VK-153481