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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A body of mass 10 kg slides along a rough horizontal surface. The coefficient of friction is 1/√3. Taking g = 10 m/s², the least force which acts at an angle of 30° to the horizontal is

Answer: (C)

Solution

The least (minimum) force to move the body, applied at the "angle of friction" θ_f = tan⁻¹(μ) = 30° (since μ=1/√3 corresponds exactly to 30°), is given by =

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Question ID VK-153526