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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body moves from a position **r₁** = (2î − 3ĵ − 4k̂) m to a position **r₂** = (3î − 4ĵ + 5k̂) m under the influence of a constant force **F** = (4î + ĵ + 6k̂) N. The work done by the force is

Answer: (A)

Solution

Displacement **r₂ − r₁** = (3−2)î + (−4+3)ĵ + (5+4)k̂ = î − ĵ + 9k̂.

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Question ID VK-153536