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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A particle acted upon by constant forces (4î + ĵ − 3k̂) N and (3î + ĵ − k̂) N is displaced from the point (î + 2ĵ + 3k̂) m to the point (5î + 4ĵ + k̂) m. The total work done by the forces in SI unit is

Answer: (B)

Solution

Resultant force **F** = **F₁+F₂** = (7î + 2ĵ − 4k̂) N. Displacement **Δr** =

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Question ID VK-153539