JEE Main Physics question
A force of (5+3x) N acting on a body of mass 20 kg along the x-axis displaces it from x = 2 m to x = 6 m. The work done by the force is
Answer: (C)
Solution
W = ∫₂⁶ (5+3x) dx = [5x + 1.5x²]₂⁶ = (30+54) − (10+6) = 84 − 16 = 68 J.