JEE Main Physics question

Physics Work, Energy and Power JEE Main

A spring with spring constant k is extended from x = 0 to x = x₁. The work done will be

(A)kx₁²
(B)½kx₁²Correct
(C)2kx₁²
(D)2kx₁

Answer: (B)

Solution

W = ∫₀ˣ¹ kx dx = ½kx₁².

Question ID VK-153562