JEE Main Physics question
A particle of mass 100 g is thrown vertically upwards with a speed of 5 ms⁻¹. The work done by the force of gravity during the time the particle goes up is
Answer: (B)
Solution
Height risen h = u²/2g = 25/(2×9.8) ≈ 1.28 m. Work by gravity = −mgh =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account