JEE Main Physics question
A running man has the same kinetic energy as that of a boy of half his mass. The man speeds up by 2 ms⁻¹ and the boy changes his speed by x ms⁻¹, so that the kinetic energies of the boy and the man are again equal. Then x in ms⁻¹ is
Answer: (A)
Solution
Let man's mass M, boy's mass M/2, with initial speeds and . Equal KE: ½² = ½(M/² ⟹ = √2·. After the change: ½+2)² = ½(M/+x)² ⟹ √+2) = +x =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account