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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. The height at which the kinetic energy of the body becomes half of the original value is

Answer: (D)

Solution

By energy conservation, ½mu² = ½mv² + mgh, i.e. (initial KE) = (KE at height h) + mgh.

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Question ID VK-153576