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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

Two springs P and Q of force constants and = /2) are stretched by applying forces of equal magnitude. If the energy stored in Q is E, then the energy stored in P is

Answer: (D)

Solution

For equal force, energy stored W = F²/(2k), so W ∝ 1/k. / = / = 1/2 ⟹ = E/2 (since = E).

Question ID VK-153585