JEE Main Physics question
A particle is moving under the influence of a force given by F = kx, where k is a constant and x is the distance moved. The energy (in joule) gained by the particle in moving from x = 0 to x = 3 is
Answer: (C)
Solution
Energy gained = work done = ∫₀³ kx dx = k[x²/2]₀³ = 4.5k.