JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

Power applied to a particle varies with time as P = (3t² − 2t + 1) W, where t is in second. Find the change in its kinetic energy between t = 2 s and t = 4 s.

Answer: (B)

Solution

ΔK = ∫ P dt = ∫(3t²−2t+1) dt = [t³−t²+t], evaluated between the two

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-153598