JEE Main Physics question
Power applied to a particle varies with time as P = (3t² − 2t + 1) W, where t is in second. Find the change in its kinetic energy between t = 2 s and t = 4 s.
Answer: (B)
Solution
ΔK = ∫ P dt = ∫(3t²−2t+1) dt = [t³−t²+t], evaluated between the two
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