JEE Main Physics question
A 16 kg block moving on a frictionless horizontal surface with a velocity of 4 m/s compresses an ideal spring and comes to rest. If the force constant of the spring is 100 N/m, then the spring is compressed by
Answer: (A)
Solution
½mv² = ½kx² ⟹ x = v√(m/k) = 4√(16/100) = 4(0.4) = 1.6 m.